I'm not convinced it's actively balancing by charging a lower voltage cell using the higher voltage cells. I watched the lowest voltage cells in your demo and they didn't go up in voltage. It looks to me like it's discharging the highest cells through the big 1R0 (1 Ohm) resistor on the board by measuring which of two neighbouring cells is higher, and is probably why it gets warm. I think the IC on the board is something like a TI BQ29209 that you can specify an external balance resistor for. TI call this "Automatic Cell Balance"
REPLY
https://www.youtube.com/channel/UCoj6RxIAQq8kmJme-5dnN0Q
https://www.analog.com/en/technical-articles/active-battery-cell-balancing.html
And none of the resistors are large enough to pull that. They are teeny tiny
REPLY
Craig Overend3 months ago
@DIY Solar Power with Will Prowse They aren't inductors on the board you have. Those three large 1R0 passive devices are wire wound resistors. I've seen the the Analog Devices link and videos about the devices years ago when it was Linear Technologies, it is a totally different device that only come in much higher pin counts, and uses transformers and integrated switching FETs to charge from one cell to the next while maintaining isolation.
REPLY
cruiser97eric13 months ago
@DIY Solar Power with Will Prowse Every inductor is also a resistor and every resistor is also an inductor. So you are both right and wrong.
REPLY
DIY Solar Power with Will Prowse
@cruiser97eric1 oh sure, but craig is saying its being used to dissipate 1.2 amps. And I doubt that. Ill just get my meter on this thing and see whats actually going on.
REPLY
DIY Solar Power with Will Prowse
@Craig Overend I think you are right. Been doing some tests today. Damn it.
REPLY
DIY Solar Power with Will Prowse
after more thinking and testing it seems Craig is totally correct